15 points need answer asap
find the product. (6m2 – 5m + 4)(–4m2 – 3m – 7)

(a) 2m2 – 8m – 3

(b) –24m4 + 2m3 – 43m2 + 23m – 28

(c) –24m2 + 15m – 28

(d) –24m4 – 38m3 – 73m2 – 47m – 28

The answer to your question is letter B

Step-by-step explanation:

Product

                     (6m² - 5m + 4) ( -4m² - 3m - 7)

1.- Multiply -4m² by each term of the first  group

           ( 6m² - 5m + 4)(-4m²) = -24m⁴ + 20m³ - 16 m²

2.- Multiply -3m by each term of the first group

          (6m² - 5m + 4) (-3m) = -18m³ + 15m² - 12m

3.- Multiply -7 by by each term of the first group

         (6m² - 5m + 4) (-7) = -42m² + 35m - 28      

4.- Simplify

      -24m⁴ + 20m³ - 16 m²  -18m³ + 15m² - 12m -42m² + 35m - 28      

     -24m⁴ + 2m³ - 43m² + 23m - 28

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply