The marketing director of a large department store wants to estimate the average number of customers who enter the store every five minutes. she randomly selects five-minute intervals and counts the number of arrivals at the store. she obtains the figures 53, 32, 41, 44, 56, 80, 46, 29, 32, and 75. the analyst assumes the number of arrivals is normally distributed. using these data, the analyst computes a 95% confidence interval to estimate the mean value for all five-minute intervals. what interval values does she get?

11 feet 6 inches and 8 feet 6 inches

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

b.-4 units

all you   do is count how many times you move