Mathematics, 13.11.2019 17:31, jasozhan
The sum of four consecutive odd integers is β72. write an equation to model this situation, and find the values of the four integers. n + n + 2 + n + 4 + n + 6 = β72; n = β21; n + 2 = β19; n + 4 = β17; n + 6 = β15 n + (n β 2) + (n β 4) + (n β 6) = β72; n = β 21; n β 2 = β23; n β 4 = β25; n β 6 = β 27 n + n + 2 + n + 4 + n + 6 = β72; n = β21; n + 2 = β23; n + 4 = β25; n + 6 = β27 n β (n + 2) β (n + 4) β (n + 6) = β72; n = β20; n + 2 = β18; n + 4 = β16; n + 6 = β14
Answers: 2
Mathematics, 21.06.2019 20:00, anabelleacunamu
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Mathematics, 21.06.2019 21:50, shay68596
What is the next step in the given proof? choose the most logical approach. a. statement: m 1 + m 2 + 2(m 3) = 180Β° reason: angle addition b. statement: m 1 + m 3 = m 2 + m 3 reason: transitive property of equality c. statement: m 1 = m 2 reason: subtraction property of equality d. statement: m 1 + m 2 = m 2 + m 3 reason: substitution property of equality e. statement: 2(m 1) = m 2 + m 3 reason: substitution property of equality
Answers: 3
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