Write a two-step equation involving multiplication and subtraction that
has a solution of x = 7.

One 3(2x + 10) - 2(x - 2) - 59  = 3

Step-by-step explanation:

First, break up 7 into two parts:

3 + 4 = 7

Then, replace 7 with x:

3 + 4 = x

Then, create more complexity:

3 + 21 - 14 = x

21-14 = x - 3

3(x) - 2(x) - x = 3

Drop the last -x and add a constant:

3(2x + 10) - 2(x - 2) - 59  = 3

Proof:

3(2(7) + 10) - 2(7 - 2) - 59 = 3

3(14 + 10) - 2(5) - 59 = 3

3(24) - 10 -

72 - 10 - 59 = 3

62 - 59 = 3

3 = 3

Hope this helps! Have an awesome day! :-)

the answer is c

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)