Find the center, vertices, and foci of the ellipse with equation x squared divided by 400 plus y squared divided by 625 = 1

x^2/400 + x^2/625

(x-0)^2/400) +(y-0^2/625)

x^2=400

X=sqrt. 400

x = 20

y^2=625

y = sqrt. 625

y= 25

a^2-c^2=b^2

sqrt 400-625 = c

20-25=c

The correct answer is c=-5

(-5,0)

(5,0)

Step-by-step explanation:

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

the answer is 62.8 cubic units