Mathematics, 13.11.2019 05:31, clickbaitdxl
Given a(-1,10) and b(x,2). find the value(s) of x if ab = 10.
Answers: 1
![A(-1,10)\textrm{ } B(x,2)\\\textrm{Length of AB=} \sqrt{(x-(-1))^2+(2-10)^2}=\sqrt{(x+1)^2+(-8)^2}=\sqrt{(x+1)^2+64}\\\textrm{Length of AB=}10\\\sqrt{(x+1)^2+64}=10\\ \textrm{Squaring both sides}\\\\(\sqrt{(x+1)^2+64 })^2=10^2\\ (x+1)^2+64=100\\\textrm{Subtracting both sides by 64}\\(x+1)^2+64-64=100-64\\(x+1)^2=36\\\textrm{Taking square root both [tex]sides}\\\sqrt{(x+1)^2}=\sqrt{36} \\ x+1=\pm6\\\textrm{Subtracting both sides by 1}\\x+1-1=\pm6-1](/tpl/images/0371/9208/d546f.png)
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Given a(-1,10) and b(x,2). find the value(s) of x if ab = 10....
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