Mathematics, 13.11.2019 04:31, cathyjuan
In the quadratic equation \[x^2 + \left(k-\frac{1}{k}\right)x - 1 = 0,\]solve for $x$ in terms of $k$.
Answers: 3
, 
, 
we have 
. hence:
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In the quadratic equation \[x^2 + \left(k-\frac{1}{k}\right)x - 1 = 0,\]solve for $x$ in terms of $k...
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