Whats the algebraic equation for: jorge has some dimes and quarters. he has 10 more dimes than quarters and the collection of coins is worth $2.40. how many dime and quarters does jorge have?

4 quarters and 14 dimes

Step-by-step explanation:

Let x be quarters and since Jorge has 10 more dimes than quarters you can say x + 10. 25 is the quarters and the 10 is the dimes.  

25x + 10(x+10) = 240

25x + 10x + 100 = 240

35x = 140

x = 4

Multiply 4 and 0.25 and you get 1.00. Subtract 1.00 from 2.40 to get 1.40. Divide that by 10 (amount of dime) to get 14.

x = 12

y = 15

step-by-step explanation:

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.