Suppose the distance x between a point target and a shot aimed at the point in a coin-operated target game is a continuous random variable with p. d.f. ) = 0.75(1 − x 2 ) −1 < x < 1 f(x) = 0 ℎ (a) compute p(x> 0) (b) compute < x < .5) (c) compute p( x< -.25 or x > .25) (d) compute e[x] and v[x] (e) determine the distribution function.

just sum

10 + 10 = 20

mathpapa

step-by-step explanation:

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7