Ab passes through a(-3.0) and b(-6, 5). what is the equation of the line that passes through the origin and is parallel to ab?
o a 5x-3y=0
b. -x + 3y = 0
c 5x - 3y = 0
d. 3x + 5y=0
e. 3x + 5y = 0

The equation of line passing through origin and parallel to first line is  5 X + 3 Y = 0

Step-by-step explanation:

Given as :

The points through which line AB passes are A ( - 3 , 0)  and  B ( -6 , 5 )

SO the slope line AB = (m1) =

Or,                                  (m1) =

Or,                                  (m1) =  

Now Another line passes through origin ( 0 , 0)

And another line is parallel to first line AB ,  so, (m2) = (m1 ) =

Now equation of another line passing through origin and slop (m2) is :

Or, Y - 0 = (X -0)

Or  - 3 Y = 5 X

∴      Y =   - X

Hence The equation of line passing through origin and parallel to first line is  5 X + 3 Y = 0   Answer

the answer is true.

step-by-step explanation:

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get