Mathematics
Mathematics, 12.11.2019 19:31, trueeriksonweav

Since the simplified numerator, x > 0 for all x, we have f ''(x) > 0 ⇔ x2 βˆ’ 1 > 0 ⇔ |x| > your answer cannot be understood or graded. more information and f ''(x) < 0 ⇔ |x| < . thus the curve is concave upward on the intervals (βˆ’[infinity], βˆ’1) and and con

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Since the simplified numerator, x > 0 for all x, we have f ''(x) > 0 ⇔ x2 βˆ’ 1 > 0 ⇔ |x|...

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