A(1,4) b (-1,2) c (5,-2) are the vertices of triangle abc find the sum of coordinates of the point where the right bisector of bc intersects the median through c

3.

Step-by-step explanation:

Find the midpoint of BC:

midpoint = (-1+5)/2, (2-2)/2 = (2, 0).

The slope of BC = (2 - -2) / (-1-5) = -2/3.

Find the equation of the right bisector of BC:

The slope = -1 / -2/3 = 3/2.

y-y1 = m(x-x1)

y - 0 = 3/2(x - 2)

y = 3/2x - 3.

Now find the equation of the median through C:

The midpoint of AB = (1 - 1)/2, (4+2)/2

= (0, 3).

The equation of the median:

The slope = (-2-3) / (5-0)

= -1.

The equation is:

y - 3 = -1(x - 0)

y -3 = -x.

Now we find the point of intersection by solving the 2 equations:

y - 3 = -x

y = 3/2x - 3

y = -x + 3

So:

3/2x - 3 = -x + 3

3/2x + x = 6

5/2 x = 6

x = 12/5.

y =  -12/5 + 3

= -12/5 + 15/5

= 3/5.

The sum of the coordinates = 12/5 + 3 /5

= 15/5

= 3.

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step-by-step explanation:

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