Iam a three- digit number. my tens digits is six more than my ones digit. my hundred digit is eigth less than my tens digit. what number am l?

Let units digit be x

x is greater than or equal to 0 and less than or equal to 9

tens digit is 5 more than units digit so

x+5<=9

x <=4

hundreds digit is eight less than x+5

x+5-8>=0

x-3>=0

x>=3

Therefore x>=3&x <=4

x={3,4}

Therefore number is either

083 or 194

But we know 083 is not a two digit number so correct answer is 194.

Hope this helps;:)

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Step-by-step explanation:

Answer : The three- digit number will be, 193

Step-by-step explanation :

Let the three digit number be, xyz

That means,

Ones digit = z

Tens digit = y

Hundred digit = x

My tens digits is six more than my ones digit. The expression will be:

y = z + 6         (1)

My hundred digit is eight less than my tens digit. The expression will be:

x = y - 8

or,

y = x + 8         (2)

Now equating equation 1 and 2, we get:

x + 8 = z + 6

z - x = 8 - 6

z - x = 2        (3)

That means, the difference of hundred digit and ones digit should be 2. Now we have to make possibilities of a number but the hundred digit can not be 0 that means x ≠ 0.

Possibility 1 : z = 3 and x = 1

Taking this possibility we get the value of 'y'.

y = x + 8

y = 1 + 8

y = 9

Now we have get x = 1, y = 9 and z = 3. So, the three digit number will be, 193.

Possibility 2 : z = 4 and x = 2

Taking this possibility we get the value of 'y'.

y = x + 8

y = 2 + 8

y = 10

Now we have get x = 2, y = 10 and z = 4. But it is not possible that y can not be equal to 10 being two digit in it.

So, further there will be no other possibility.

Hence, the three- digit number will be, 193

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: