Each of 11 refrigerators of a certain type has been returned to a distributor because of an audible, high-pitched, oscillating noise when the refrigerators are running. suppose that 7 of these refrigerators have a defective compressor and the other 4 have less serious problems. if the refrigerators are examined in random order, let x be the number among the first 6 examined that have a defective compressor.

The correct answer is 1,51%

Step-by-step explanation:

To get the probability  equally likely of the first 6 examined that have a defective compressor, we use the following formula

P=# of possibilities that meet the condition / #of equally likely possibilities.

As there are multiple events ,  and all must be achieve, we multiply the probabilities.

P1=7 / 11

P2=6 / 10

P3=5 / 9

P4=4 / 8

P5=3 / 7

P6=2 / 6

P(x)=7 / 11*6 / 10*5 / 9*4 / 8*3 / 7*2 / 6=0,01515151515

P(x)=1,51%

45.3592

step-by-step explanation:

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: