The massless spring of a spring gun has a force constant k = 0.09 n/cm. when the gun is aimed vertically, a 29 g projectile is shot to a height of 5.0 m above the end of the expanded spring. how much was the spring compressed initially? (find d, in meters.)

ou would have 12 of each

answer: it is d

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation