15 point, need this answered asap
write an equation of an ellipse in standard form with the center at the origin and with the given characteristics. vertex at (-3,0) and co-vertex (0,2)
a. x^2/9+y^2/4=1
b. x^2/4+y^2/9=1
c. x^2/3+y^2/9=1
d. x^2/2+y^2/3=1

Option A

The equation of ellipse in standard form is

Solution:

Given, We have to write an equation of an ellipse in standard form with the center at the origin

Given that vertex at (-3,0) and co-vertex (0,2)

The standard form of an ellipse is

where a is x- intercept and b is y – intercept.

We have vertex (-3, 0) and (0, 2) from these we can say that, x – intercept is – 3 and y – intercept is 2 . As we know that intercepts are the respective values when other variables becomes 0.

Now, let us find our ellipse equation:

Hence, the standard form equation is

Thus option A is correct

neither i nor ii 56 / 4.9 = 11.91489362 and 82 / (11+5) =5.125 so i is wrong

ii. (24/8+2) times 3 = 15 and (42+9)/2 =25.5

step-by-step explanation:

56

wheres graph

step-by-step explanation: