Joy is preparing 20 liters of a 25% saline solution. she has only a 40% solution and a 10% solution in her lab. how many liters of the 40% solution and how many liters of the 10% solution should she mix to make the 25% solution?

10 liters of 40% solution

10 liters of 10% solution

Step-by-step explanation:

Let's say x is the liters of 40% solution, and y is the liters of 10% solution.

Write equations using the volume and amount of salt:

x + y = 20

0.40 x + 0.10 y = 0.25 (x + y)

Solve the system of equations.

0.40 x + 0.10 (20 − x) = 0.25 (x + 20 − x)

0.40 x + 2 − 0.10 x = 0.25 (20)

0.30 x + 2 = 5

0.30 x = 3

x = 10

y = 10

You need 10 liters of 40% solution and 10 liters of 10% solution.

Joy needs 10 liters of 40% solution and 10 liters of 10% solution to make  20 liters of a 25% saline solution

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Molarity shows the number of moles of solute in every 1 liter of solution.

Molarity of a mixture of 2 solutions can use the formula.

Vc Mc = V1. M1 + V2. M2

Vc = mixed volume

Mc = mixed volume

V1 = volume of solution 1

M1 = Molarity of solution1

V2 = volume of solution 2

M2 = Molarity of solution 2

Joy is preparing 20 liters of a 25% saline solution. She has only a 40% solution and a 10% solution in her lab, then :

Mc = 25%

Vc = 20 L

M1 = 40%

M2 = 10%

Vi+V2 = 20 L ⇒ V2= 20 - V1

Calculate the molarity of a solution

link

link

link

link

link