Aball was thrown upward and its height is modeled by the function h(t) = -4.9t^2 + 58.8t + 98, where h is the height of the ball in meter and t is the time in seconds that the ball is in the air. find the maximum height of the ball to the nearest meter.

274 meters

Step-by-step explanation:

The function is a downward parabola.  So the highest point is at the vertex.

t = -b / (2a)

t = -(58.8) / (2 × -4.9)

t = 6

Evaluate the function at that point:

h(6) = -4.9 (6)² + 58.8 (6) + 98

h(6) = 274.4

Rounded to the nearest meter, the maximum height reached is 274 meters.

69.64%

step-by-step explanation:

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy