To the nearest hundredth, what is the distance between point (-6, -1) and point (4, 3)?

Hi   , the answer is 10.7  

Step-by-step explanation:

the   distance between 2 points   is

the square  root (y2-y1)^2 + (x2-x1)^2

(-6,-1) -> (x1,y1)  

(4,3)  ->(x2,y2)  

so (3- - 1 ) ^2  + (4 - -6)^2 = 4^2 + 10^2 = 16+100 = 116

the square root for 116  =  10.7

thanks  

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2