The points p(2,3) , q(-1,1) and r(5,-1) are the vertices of a triangle pqr. find the equation of the altitude of the triangle pqr drawn from the point q(-1,1).

Step-by-step explanation:

The slope of straight line PR where P(2,3) and R(5,-1) are two vertices of triangle PQR will be =

Therefore, the slope of the altitude passing through Q(-1,1) will be {Since, the product of slopes of two perpendicular straight line is -1}

So, equation of the altitude is where c is a constant.

Now, putting x = -1 and y = 1 in the above equation we get  

⇒

Therefore, the equation of the altitude is (Answer)

cut 138 centimeters off

step-by-step explanation:

250-112 = 138