Aball is dropped off the side of a bridge.
after falling 1.55 s, what is its velocity?

15.19 m/s

Step-by-step explanation:

, where is the final velocity, is the initial velocity, a is the constant gravitational acceleration 9.8 m/s^2, and t is the time (seconds).

Since the ball is dropped off the bridge, its initial velocity is 0:

We can plug in 9.8 m/s^2 into a and 1.55 s into t:

= 15.19 m/s

360 different combinations

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.