Equation 1: 8x+2y=308x+2y=30
equation 2: 7x+2y=247x+2y=24

which variable pair should we try to eliminate?

the x's because the coefficients are the same.

the y's because the coefficients are the same.

the x's because the coefficients are different?

the y's because the coefficients are different?

now that we've eliminated the variable pair, what is the resulting equation?

15y+4y=5415y+4y=54

x+4y=54x+4y=54

4y=64y=6

consider the following system of equations:

equation 1: 8x+2y=308x+2y=30
equation 2: 7x+2y=247x+2y=24

what is the solution to the system?

(6,8)

(6,-9)

(1,11)

(0,12)

Part a) We should try to eliminate the y's because the coefficients are the same

Part b) The solution is the point (6,-9)

Step-by-step explanation:

Part a) Which variable pair should we try to eliminate?

we have

----> equation 1

----> equation 2

Solve by elimination

We should try to eliminate the y's because the coefficients are the same

Part b) What is the solution to the system?

Multiply equation 2 by -1 both sides

-----> equation 3

Adds equation 1 and equation 3

Find the value of y

The solution is the point (6,-9)

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

the answer is 489

step-by-step explanation: