Train green arrow leaves station a for b everyday at 7am. on a certainday it was delayed by 2 hours. to coverup the time it increases its speed by 20% bt still arrived at b station 1hours later than the scheduled time. what is the usual duration of train's journey from station a to b? ?

a)6hrs
b)7hrs
c)8hrs
d)9hrs
e)none of these

The usual duration of the train journey from station A to B is hours.

Step-by-step explanation:

Lets try to understand with a real life example of the question then we will frame it in terms of variables.

As given the train starts from am and reached the destination at pm.

When it is late by two hours it started its journey at am so will reach at pm as it has already covered up with an hour due to increased in its speed then actually it reached at pm.One hour late from its scheduled time.

Lets frame an equation.

Knowing the fact distances are same for both of the station.

And

Now we take as our normal day speed and speed when the train is late, is added with the previous speed.

Similarly with time as our normal time and when the train is running late from its scheduled time.

Now

on normal days.

when the train is late.

Equating both the equations as distances are same.

We have

Subtracting from both sides.

Taking as common terms.

The remaining equation is

Adding both sides

So the journey fro station A to b is of hours.

probably .5

i can on others if necessary.