Aresearcher is interested in estimating the mean weight of a semi tracker truck to determine the potential load capacity. she takes a random sample of 17 trucks and computes a sample mean of 20,000 pounds with sample standard deviation of 1,500. she decides to construct a 98% confidence interval to estimate the mean. the degrees of freedom associated with this problem are

The degrees of freedom associated with this problem are 16.

Step-by-step explanation:

The degrees of freedom associated with a problem, independent of the confidence level, is the sample size subtracted by 1.

In this problem, we have that:

She takes a random sample of 17 trucks, so the sample size is 17.

This means that the degrees of freedom associated with this problem are 16.

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.