To study the metabolism of insects, researchers fed cockroaches measured amounts of a sugar solution. after 2, 5 and 10 hours, they dissected some of the cockroaches and measured the amount of sugar in various tissues. five roaches fed the sugar d-glucose and dissected after 10 hours had the following amounts, in micrograms, of d-glucose in their hindguts: 55.95, 68.24, 52.73, 21.50 and 23.78.assume the d-glucose content follows a normal distribution, construct a 95% confidence interval for the mean amount d-glucose in cockroach hindguts under these conditions.

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation:

2500

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.