At the city museum, child admission is $5.20 and adult admission is $9.30. on thursday, 149 tickets were sold for a total sales of $1176.60. how many adult tickets were sold that day?

The Answer is: There are 51 child tickets and 98 adult tickets.

Step-by-step explanation:

Let c = the number of child tickets and a = the number of adult tickets. Adding these tickets up is equal to 149 total tickets.

a + c = 149.

Solve for a:

a = 149 - c

The number of child tickets times 5.20 plus the number of adult tickets times 9.30 is equal to $1,176.60. Equation below:

5.20c + 9.30a = 1176.60

5.20c + 9.30(149-c) = 1176.60

5.20c + 1385.7 - 9.30c = 1176.60

-4.1c = 1176.60 - 1385.7

-4.1c = -209.1

c = -209.1 / -4.1 = 51 child tickets.

Solve for a:

a = 149 - c

a = 149 - 51 = 98 adult tickets.

Proofs:

a + c = 149

98 + 51 = 149

And:

5.20c + 9.30a = 1176.60

5.20(51) + 9.30(98) = 1176.60

265.20 + 911.40 = 1176.60

1176.60 = 1176.60

srry idk

step-by-step explanation:

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.