In a raffle where 2000 tickets are sold for $2 each, one first prize of $400 and one second prize of $200 will be awarded. what is the expected value of a single ticket in the raffle? round your answer to the nearest hundredth, and do not include a $ sign or the word "dollars" in your response.

The expected value is -$1.7

Step-by-step explanation:

Consider the provided information.

In a raffle where 2000 tickets are sold for $2 each,

One first prize of $400 and one second prize of $200 will be awarded.

Suppose you bought a ticket for $2 and win first price, Then the gain will be: $400-$2=$398

Suppose you bought a ticket for $2 and win second prize, then the gain will be:

$200-$2=$198

Suppose you bought a ticket for $2 and you got nothing, the the loss will be -$2.

The probability of getting first prize is:

Because only one person is selected for first prize out of 2000.

The probability of getting second prize is:

The probability of getting nothing is:  

Hence the expected value is:

Hence, the expected value is -$1.7

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.