Aline passes through the point (-4, -8) and has a slope of 5/2 write an equation in slope intercept form for this line

y = 5x/2 + 2

Step-by-step explanation:

We know the equation for slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Since we have the coordinates of one point on this line and the slope, we can substitute that in and find b first:

y = mx + b

-8 = 5/2(-4) + b

-8 = -10 + b

b = 2

So we can use the slope and this y intercept we found to plug back into the equation:

y = mx + b

y = 5x/2 + 2

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true