Amachine is used to fill containers with a liquid product. fill volume can be assumed to be normally distributed. a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.

(a) suppose that the manufacturer wants to be sure that the mean net contents exceeds 12 oz. what conclusions can be drawn from the data (use α= 0.01).

(b) construct a 95% two-sided confidence interval on the mean fill volume.

There is no statistical evidence at 1% level to accept that    the mean net contents exceeds 12 oz.

Step-by-step explanation:

Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.

We find mean = 11.015

Sample std deviation = 3.157

a)

(Right tailed test)

Mean difference /std error = test statistic

p value =0.174

Since p >0.01, our alpha, fail to reject H0

Conclusion:

There is no statistical evidence at 1% level to accept that    the mean net contents exceeds 12 oz.

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

(-1,-0.5)

step-by-step explanation: