What is the constant of variation, k, of the direct variation, y = kx, through (–3, 2)?

k = –k equals negative startfraction 3 over 2 endfraction.
k = –k equals negative startfraction 2 over 3 endfraction.
k = k equals startfraction 2 over 3 endfraction.
k = k equals startfraction 3 over 2 endfraction.

56

step-by-step explanation:

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder