The length of a rectangle is eight more
thon twice its width. the perimeter is 95
feet. find the dimensions of the rectangle.
variable
equation:
solution

Width of the rectangle =  13.16 ft

Length of the rectangle =  34.33 ft

Step-by-step explanation:

Let the width of the rectangle = k ft

So, the length of the rectangle =  (2k + 8) ft

Perimeter of the rectangle = 95 ft

PERIMETER OF THE RECTANGLE = 2(LENGTH +WIDTH)

⇒ 2( k+ (2k+ 8))  = 95

or,  2( 3k + 8) = 95  ⇒  6k + 16 = 95

or, 6k = 95 - 16 = 79

⇒ k = 79/ 6 = 13.16

So, the Width of the rectangle = k = 13.16 ft

Now, Length of the rectangle = 2(13.16)+ 8 = 34.33 ft

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6 equilateral triangles