The life in hours of a 75-watt light bulb is known to be approximately normally distributed, with standard deviation of 25 hours. a random sample of 62 light bulbs has a mean life of 1014 hours. construct a 98% confidence interval around the true population mean life of the light bulb.

385

Step-by-step explanation:

We have to find the Sample size through the formula of Margin Error.

The formula is,

We have all the values,

ME = 2.5 hours

cl = 98% that is in Z-table equal to 2.32

Replacing,

clearing n,

So the least sample size is at least of 385.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

y∈r, 8> y≥0

hope i !

p.s the first bit only matters if you know what that means.

p.p.s brainliest would really