Aball is thrown upward and outward from a height of 8 feet. the height of the ball, f(x), in feet, can be modeled by 1(x) -0.1x2+14x+8 where x is the ball's horizontal distance, in feet, from where it was thrown use this model to solve parts (a) through (c). a. what is the maximum height of the ball and how far from where it was thrown does this occur? feet from the point of release. feet, which occurs the maximum height is (round to the nearest tenth as needed)

Step-by-step explanation:

A graphing calculator can show the answers to these questions.

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For quadratic ax²+bx+c, the x-value of the vertex is ...

  x = -b/(2a)

For the given expression, the vertex is ...

  x = -14/(2(-0.1)) = 70

The distance from the point of release to the point of maximum height is 70 feet.

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The height of the ball at that point is ...

  f(70) = (-0.1·70 +14)70 +8 = 7·70 +8 = 498 . . . . feet

The maximum height is 498 feet.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?