Given square abcd with diagonals ac, bd.
if db = 7x + 1 and ae = 2x + 11, find eb.

The length of EB is 25 unit

Step-by-step explanation:

Given as:

ABCD is a square With diagonal AC and BD

The length of DB = 7x + 1

The length of AE = 2x + 11

The mid point of BD and AC is E

Let the each side of square be m

So, BD² = m² + m²

Or, (7x + 1) = 2 m²

Or m²   =

Again

AC² = m² + m²  = 2 m²

Or, AC = (7x + 1)

∵ AE is the half of diagonal AC

So, AE =  × (7x + 1)

Or, 2x + 11 =    × (7x + 1)

or , 4x + 22 = 7x + 1

Or,  3x = 21  

∴       x = 7 unit

So, BD = 7 (7 ) + 1 = 50 unit

So, BE  is the half of diagonal BD

Or, BE =    × 50 = 25 unit

Hence The length of EB is 25 unit Answer

step-by-step explanation:

this is not a question

95.03 is the answer. hope this !