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explain how system 1 becomes equivalent to system 2.

system 1:
lx + my = n
ax + by = c

system 2:
(l − a)x + (m − b)y = n − c
lx + my = n

a. the first equation in system 2 is the sum of the equations in system 1. the second equation in system 2 is the first equation in system 1.

b. the first equation in system 1 is the difference of the equations in system 2. the second equation in system 1 is the first equation in system 2.

c. the first equation in system 2 is the difference of the equations in system 1. the second equation in system 2 is the first equation in system 1.

d. the first equation in system 1 is the sum of the equations in system 2. the second equation in system 1 is the first equation in system 2.

B is your answer

Step-by-step explanation:

Think it thru and u will remember it ok

Option C is the answer.

Step-by-step explanation:

System 1 :

Lx + My = N (1)

Ax + By = C (2)

System 2 :

(L - A)x + (M - B)y = N - C (3)

Lx + My = N (4)

If we subtract equation (2) from equation (1),

(Lx + My) - (Ax + By) = N - C

Lx - Ax + My - By = N - C

(L - A)x + (M - B)y = N - C

Which is similar to equation (3) of the system 2.

And equation (1) of the system (1) is similar to the equation (4) of the system (2)

Therefore, equation (3) of the system 2 is the difference of of equations in the system 1. Equation (1) for system 1 is similar to the equation (4) of the system 2.

Option C is the answer.

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6