The longest side of a triangle is 4 more than twice the shortest. the third side is 3 more than the shortest. the perimeter is 31. find all sides of the triangle.

The shortest side = 6

The third side = 9

The hypotenuse (the longest side) = 16

Step-by-step explanation:

First, let's establish the following based on the information given:

The shortest side = x

The third side = (x + 3)

The hypotenuse (the longest side) = (2x + 4)

The perimeter = 31

Since the perimeter is the total of all 3 sides, we are left with this equation:

(x) + (x + 3) + (2x + 4) = 31

From here, combine like-terms and solve for x.

(x) + (x + 3) + (2x + 4) = 31

(4x + 7) = 31

4x = 24

x = 6

Now that we know the value of x, we can apply this to the predetermined formulas to find the measurements of the remaining two sides.

The shortest side = 6

The third side = (x + 3) = 9

The hypotenuse (the longest side) = (2x + 4) = (2(6) + 4) = (12 + 4) = 16

To check, add all of the sides together to make sure they equal 31.

6 + 9 + 16 = 31

~Hope this Helps!~

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5