Abaseball player running forward at 3 meters per second throws a ball with a velocity of 20 meters per second at an angle of 20o with the horizontal. what is the resultant speed and direction of the throw?

22.8 m/s at 17.4°

Step-by-step explanation:

Horizontal component:

vₓ = 3 + 20 cos 20° = 21.8

Vertical component:

vᵧ = 0 + 20 sin 20° = 6.84

Magnitude:

v² = vₓ² + vᵧ²

v² = (21.8)² + (6.84)²

v = 22.8 m/s

Direction:

θ = atan(vᵧ / vₓ)

θ = atan(6.84 / 21.8)

θ = 17.4°

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

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