Asystem in a noisy environment transmits or when 1 or 0are transmitted to decrease the probability of error. suppose theprobability that one of the 5 transmitted bits is corrupted from 1 to 0 is0.3 and the probability that a bit is corrupted from 0 to 1 is 0.1. given thatthe probability that the system transmits a 0 or a 1 is equally likely, if01101 was received what is the probability that a 1 was transmitted

step-by-step explanation:

the answer is 128

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)