Given p(a)= 0.4 and p(b) = 0.3 , if a and b are mutually exclusive events compute p(aorb)

For mutually exclusive events,  P(A or B)    = 0.7

Step-by-step explanation:

P(A) = 0.4

P(B) = 0.3

Here, A and B are mutually exclusive events.

⇒ A  ∩  B = Ф

    P(A  ∩  B) = 0

So, P(A or B)  = P(A) + P(B) - P(A ∩B)

=  0.4 + 0.3  - 0

= 0.7

⇒ P(A or B)  = 0.7

Hence, for mutually exclusive events,  P(A or B)    = 0.7

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation:

the answer on ed. is:

c. "the graph of f(x) has exactly two x-intercepts."

hope i could someone! : )