Arandom sample of 85 adults found that the average calorie consumption was 2100 per day. previous research has found a standard deviation of 450 calories, and you use this value for \sigma σ. a researcher wants to estimate a 95% confidence interval and is willing to accept a margin of error of \pm 50 ± 50 calories. she knows it will cost $50 to survey each member of the sample. given this information, how much will it cost to survey the minimum number of people?

$15600

Step-by-step explanation:

Minimum number of samples can be calculated using the formula:

N≥ where

N≥ =311.2

Therefore, minimum required sample size for 50 cal standard error in 95% confidence is 312

Since the survey costs $50 for each person then the survey costs minimum

50*312=$15600

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

what do u need to know

step-by-step explanation: