The first four terms of an arithmetic sequence are 28, 20, 12, and 4. which term of the sequence is -36?

9th term in the given sequence is -36.

Step-by-step explanation:

Here the first four terms of the sequence is  28, 20 , 12 and 4

Now, a2 -a1 = 20 - 28 = -8

         a3 - a2 = 12- 20 = -8

⇒ Here, d = - 8 , a = 28

Now, n th term in an AP :

Here a(n) = -36

⇒ -36 = 28 + (n-1)(-8)

or,  -36  = 28  - 8n +8

or, 8n = 28 + 8 + 36 = 72

or, n = 72/8 = 9

⇒ n = 9

Hence, the 9th term in the given sequence is -36.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: