Three more problems i’m having trouble with

The first one:

15 - [(3 + 4) * 2] = 1

15 - [(7) * 2]

15 - 14 = 1

The second one:

[(15 * 10) divided by 5] - 5 = 25

15 * 10 = 150

150/5 = 30

30 - 5 = 25

The third one:

18 - [6 + (81 divided by 81)] = 11

81/81 = 1

6 + 1 = 7

18 - 7 = 11

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

so, converting firstly the mixed fractions to improper fractions and then "adding".