The equation of line ab is y = 5x + 1. write an equation of a line parallel to line ab in slope-intercept form that contains point (4, 5).

y = 5x − 15
y = 5x + 15
y = 1 over 5x + 21 over 5
y = 1 over 5x − 29 over 5

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand, we have that if two lines are parallel then their slopes are equal.

Given the line AB: the slope is

Therefore, a parallel line will have slope

Thus, the equation is of the form is:

We substitute pointand find "b":

Finally, a line parallel to line AB is:

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.