The daily revenue at a university snack bar has been recorded for the past five years. records indicate that the mean daily revenue is $2700 and the standard deviation is $400. suppose that 100 days are randomly selected. what is the probability that the average daily revenue of the sample is higher than $2600?

0.9938

Step-by-step explanation:

Let x be the random variable that represents the daily revenue at a university snack bar.

As per given , we have

, and n= 100

Using formula ,

z-score for x= 2600

The probability that the average daily revenue of the sample is higher than $2600 :

  [P(Z>-z)=P(Z<z)]

Therefore, the probability that the average daily revenue of the sample is higher than $2600 = 0.9938

q1 a person or thing situated away or detached from the main body or system. a cluster is a a mash of many things.

q2 do

step-by-step explanation:

it is true

step-by-step explanation:

all the combinations add up i used   calculator