Suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $65. for one performance, 25 advance tickets and 40 same-day tickets were sold. the total amount paid for the tickets was $2150. what was the price of each kind of ticket?
The Answer is: Price of Advanced Tickets: $30. Price of Same Day tickets: $35.
Amount of Advanced + Amount of Same = $65
a + s = $65
a = 65 - s
25 tickets times the adult price plus 40 tickets at the same day price equals $2,150. Setup the equation, substitute, and solve for s:
25a + 40s = $2150
25(65-s) + 40s = 2150
1625 - 25s + 40s = 2150
15s = 2150 - 1625
15s = 525
s = 525 / 15 = $35.
a = 65 - 35 = $30.
25(30) + 40(35) =
$750 + $1,400 = $2,150
first i plotted all my points on a grid graph
i made sure all of them were in the correct quadrant
then i saw it was a trapezoid or a quadrilateral