1. the stopping distance, d, in feet of a car is directly proportional to
the square of its speed, v.

a- write the direct variation equation for the scenario above.

b- when there is a car accident, it is important to figure out how
fast the cars involved were traveling. using the direct variation
equation above, solve for speed.

A: The variation equation is

B: The speed is

Step-by-step explanation:

Part A:

The stopping distance is directly proportional to the square of the speed. Mathematically this means the distance is equal to the square of speed multiplied by a proportionality constant , thus

Part B:

Once we have the equation relating and , then it is easy to solve for using that equation.

Rearranging the equation we got in Part A and solving for we get:

o= 4(i) +3

step-by-step explanation:

o is your output value and i is your input value. so, for example, if we stuck 7 in as our input, we would first multiply by 4 ( pemdas ), which equals 28. then we would add 3 to 28, for a total output of 31. this may not be a graph, but, it is a way to solve your formula..

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.