If you are given the graph of h(x)=log6x, how could you graph m(x)=log6(x+3)?

translate each point of the graph of h(x) 3 units up.
translate each point of the graph of h(x) 3 units down.
translate each point of the graph of h(x) 3 units right.
translate each point of the graph of h(x) 3 units left.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )