X-intercept of (2,0) and (8,0); passes through (5,-9)

Since there’s two x-intercept, it must be a quadratic graph which requires a quadratic equation.

ax^2 + bx + cx = 0

The 0 represents y as y is shown to be 0 from the information above.

According to the info provided, y and x have been given, we know that at some point, x is either 2 or 8 when y is 0.

The way we determine the answers of a quadratic equation is factorising the quadratic expression into 2 linear expressions.
Therefore, we have to find the linear equations that make up the quadratic equations:

x = 8 , x = 2

We will have to reverse it:

x - 8 = 0 , x - 2 = 0

Since we clearly know that y is 0, we can represent 0 as y

x - 8 = y , x - 2 = y

So to get the equations, we just have to take the expression before the equivalent to y and multiply them to get the quadratic equation as y is redundant here.

So:
x - 8 and x - 2

are our equations

Now, we multiply them:

(x - 8)(x - 2) = x^2 + 10x + 16

So our quadratic equation is

x^2 + 10x + 16.

Hope this helps, and have a great day ahead :D

put like terms together.orremember that the 45 becomes negative when moved to the other side.orthe minuses cancel out.

It’s 5 points actually