Lashonda is going to rent a truck for one day. there are two companies she can choose from, and they have the following prices. company a has no initial fee but charges 60 cents for every mile driven. company b charges an initial fee of $75 and an additional fee of 40 cents for every mile driven. for what mileages will company a charge more than company b? use m for the number of miles driven, and solve your inequality for m.

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The mileage for which the company A will charge more is 125

Step-by-step explanation:

Given as :

The charge of company A = 60 cents per mile

The charge of company B = 40 cents per mile + $75

Now , Let the number of miles driven = m

So, 60 m = 40 m + $ 75

∵ 1 $ = 100 cents

Or , 60 m - 40 m = 75 × 100 cents

Or,  20 m    =  7500 cents

∴          m     =

or, Number of miles driven = 375 miles

The charge of company A = 60 × 375 = 22,500 cents

The charge of company B = 40 × 375 + 7500 = 22,500 cents

So, Here Both company charge is same  

Now Let The mileage for which company charge more = m'

SO,   60 × (375 - m') = 40 × 375

or,     22500 - 60 m'= 15000

Or,      60 m' = 7500

So ,          m' = = 125

Hence The mileage for which the company A will charge more is 125 Answer

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.