An upright cylinderical tank with radius 7 m is being filled with water at a rate of 2 m^3/min. how fast is the height of the water increasing? (round the answer to four decimal places. )

0.0130 m per min. to  4 decimal places.

Step-by-step explanation:

If  2 m^3 of water is added we have volume = 2 = π 7^2 h   where h is the height:

h = 2 / (π 7^2) =  0.01299 m.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)